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The oxide layer conducts electrical current between neighboring transistors

The oxide layer prevents a short circuit between the substrate and the

gate in a transistor

Which of the following is NOT a correct statement about the metal

layer in a MOS circuit?

The metal layer serves as the gate in a pass transistor

The metal layer is directly connected to the semiconductor layer

The metal layer provides wires for communicating signals between transistors

The metal layer is at the top of a transistor

Most of the following statements about integrated circuits are

correct, but one is not. Which statement is NOT true?

Wires that carry signals may be embedded in a substrate without a short

circuit because a short circuit would require a signal to cross a

reverse biased junction

Each transistor on an integrated circuit is manufactured individually,

one at a time

Transistors are constructed in a small area of an integrated circuit,

and are connected to other transistors by wires that are embedded in

the integrated circuit

An integrated circuit contains several layers

Positive charge carriers are positrons (the antimatter electron)

Which is NOT correct?

Negative charge carriers are electrons

Electrical current can be carried by either negative or positive charge carriers

A hole is a position in a semiconductor which could hold an electron

but where the electron is not present

Which is NOT a characteristic of a semiconductor?

Some electrons are weakly bound to atoms, and can move through the

substance in the presence of an electric field

Most electrons are tightly bound to atoms and not available as charge

carriers for electric current

A semiconductor is made by doping silicon, so that some of the

atoms in the crystal have either one extra electron, or one fewer electron

A pure silicon crystal is a semiconductor

An advantage of using indentation to determine program structure is

If braces (or other punctuation) are used to determine the program structure,

there is a risk that the indentation could be inconsistent with the braces,

making the program hard to read.

If braces are used to determine program structure, the language is

ambiguous and the compiler cannot translate it

In the OrderedLists program (the program for the assessed exercise),

the high level algorithm for CmdDelete contains the following statement,

where q is a pointer to the node being deleted.

   ReleaseNode(q)

What would happen if this statement were omitted?

The node that q points to would remain in the list, and the

Delete command would have no effect

The program would crash immediately

The node that q points to would be deleted from the list, but

at some time in the future a call to NewNode might fail with

an "Out of heap" error even though there is a node that could

be reused

Suppose R1 contains a pointer to a node. Which of the following will

release this node by inserting it into the avail list?

    load   R2,avail[R0]
    store  R2,1[R1]
    store  R1,avail[R0]

    load   R2,avail[R0]
    lea    R2,1[R1]
    store  R1,avail[R0]

    lea    R2,avail[R0]
    store  R2,1[R1]
    store  R1,avail[R0]

Consider the following program.

i := 0;
while i<10 do
    { print (i);
      i := 5;
      print (i);
      i := 50;
      print (i); }

The output is

0 5

0 5 50

In the OrderedLists program, the high level algorithm for the Print command

begins with the statement p := *p.next. What is the purpose of this statement?

At first, p is a pointer to the header, and this statement skips over

the header and makes p point to the first node in the list (or makes p

nil if the list is empty)

If this statement is omitted, the program might crash

The statement is optional, but just makes the program run faster