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In the following table record the likelihood of producing a zygote with the various sex aneulploidies due to a single non-disjuction (ND) event.
Make sure your answer is recorded as a PERCENTAGE (fractions or decimal places are not permitted).
You are to assume that meiosis continues in the other parent normally (i.e. there will be no double non-disjunctions). Further, if a nondisjunction occurs during Meiosis I, you are to assume the Meiosis II continues normally and vice versa.
Make sure that your answer is only a number. Written words, punctuation marks or the inclusion of the percentage sign, will result in your answer being recorded incorrect.
ND in Meiosis I of Mother | ND in Meiosis I of Father | ND in Meiosis II of Father | |||
If sperm carries X chromosome | If sperm carries Y chromosome | If ND is between X & Y chromosomes | If ND is between X chromosome | If ND is between Y chromosome | |
Turner syndrome (X0) | % | % | % | % | % |
Klinefelter syndrome (XXY) | % | % | % | % | % |
Triple X syndrome (XXX) | % | % | % | % | % |
Double Y syndrome (XYY) | % | % | % | % | % |
Single Y syndrome (Y0) | % | % | % | % | % |
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