Check all the true claims about the execution of the C code provided below.
--
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
int funnyAllocation(char *buf, int b) {
buf = (char *) ( malloc(sizeof(char) * 5));
strcpy(buf, "hello");
return 7;
}
int main( int argc, char*argv[] ) {
int b = 3;
char *buf = (char *) ( malloc(sizeof(char) * 5));

int returned = funnyAllocation(buf, b);
printf("The content of buf is: %s\n", buf);
}

Question

Check all the true claims about the execution of the C code provided below.

--

#include <stdlib.h>

#include <string.h>

#include <stdio.h>

int funnyAllocation(char *buf, int b) {

buf = (char *) ( malloc(sizeof(char) * 5));

strcpy(buf, "hello");

return 7;

}

int main( int argc, char*argv[] ) {

int b = 3;

char *buf = (char *) ( malloc(sizeof(char) * 5));

int returned = funnyAllocation(buf, b);

printf("The content of buf is: %s\n", buf);

}

Answer

argc is not used

Answer

The execution can provoke a memory allocation error

Answer

hello is printed in the standard output

Crowdly