For this question, refer to the following code:

mutex_t m;
int slot = -1;
int array[2] = { 0, 0 }; // initialize to 0, 0 contents
function1() {
   mutex_acquire(&m);
   slot++;
   mutex_release(&m);
   int tid = get_counter();
   mutex_acquire(&m);
   array[slot] = tid;
   mutex_release(&m);
}

Assume that get_counter() has its own internal locking (not shown), and will return 1 when first called, and 2 when called next, etc. Assume that function1() is called by two threads at roughly the same time. What are the final contents of the array?