Určete Taylorův polynom druhého stupně funkce
f(x)=\sin(7x-\frac{\pi}{2})+8. se středem v bodě a=\frac{\pi}{6} .

Question

Určete Taylorův polynom druhého stupně funkce
  f(x)=\sin(7x-\frac{\pi}{2})+8.  se středem v bodě   a=\frac{\pi}{6} .

Answer

\frac{15}{2}-\frac{7\sqrt 3}{2}(x-\frac{\pi}{6})-\frac{49}{4}(x-\frac{\pi}{6})^2

Answer

8+\frac{\sqrt 3}{2}-\frac{7}{2}(x-\frac{\pi}{6})-\frac{49\sqrt 3}{2}(x-\frac{\pi}{6})^2

Answer

8+\frac{\sqrt 3}{2}-\frac{7}{2}(x+\frac{\pi}{6})-\frac{49\sqrt 3}{2}(x+\frac{\pi}{6})^2

Answer

8+\frac{\sqrt 3}{2}-\frac{1}{2}(x-\frac{\pi}{6})-\frac{\sqrt 3}{4}(x-\frac{\pi}{6})^2

Answer

8+\frac{\sqrt 3}{2}-\frac{7}{2}(x-\frac{\pi}{6})+\frac{49\sqrt 3}{4}(x-\frac{\pi}{6})^2

Answer

8+\frac{\sqrt 3}{2}-\frac{7}{2}(x-\frac{\pi}{6})-\frac{49\sqrt 3}{4}(x-\frac{\pi}{6})^2

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