4 NH 3 (g) + 7 O 2 (g) → 4 NO 2 (g) + 6 H 2 O(g) Δ H = -1389 kJ ...
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| Ammonia reacts with oxygen as follows. Determine the enthalpy change (kJ) for the production of 4.70 g of NO2(g). | Ammoniak reageer met suurstof soos volg. Bepaal die entalpieverandering (kJ) vir die produksie van 4.70 g NO2(g). |
4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O(g) ΔH = -1389 kJ
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