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Consider a function f : R → R f: R \to R , f ( x ) = x 2 f(x) = x^2 . Determin...

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Consider a function f:R→Rf: R \to R, f(x)=x2f(x) = x^2.

Determine the correct sequence to prove the following statement.

ff is not surjective.

If a statement is not used in the proof, you have to choose "Not used".

Consider a real number 1 in the co-domain and let f(x)=1f(x) = 1.

We cannot find any pre-image in the domain for f(x)=−1f(x)=-1.

Consider a real number −1-1 in the co-domain and let f(x)=−1f(x)=-1.

ff is not surjective

We can find two different pre-images in the domain: x=1x=1 and x=−1x=-1.

ff is not injective

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