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Consider a function f : R → R f : R → R f: R \to R , f ( x ) = 2 x + 8 f ( x )...

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Consider a function f:R→Rf:R→Rf: R \to R, f(x)=2x+8f(x)=2x+8f(x) = 2x+8.

Determine the correct sequence to prove the following statement.

fff is surjective.

If a statement is not used in the proof, you have to choose "Not used".

a=ba=ba = b

x=y−82x=y−82x = \frac{y-8}{2} exists

Consider an arbitrary real number yyy.

Assume that f(a)=f(b)f(a)=f(b)f(a)=f(b).

Consider two arbitrary real numbers aaa and bbb.

fff is surjective

Assume f(x)=yf(x)=yf(x)=y.

2a+8=2b+82a+8=2b+8

2x+8=y2x+8=y

ff is injective

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