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Calculate the change in enthalpy for the following reaction, using the appropriate standard enthalpies of formation given below. ΔfH°[FeCℓ3(s)] = -412 kJ mol-1 ΔfH°[FeCℓ2(s)] = -360 kJ mol-1 ΔfH°[HCℓ(aq)] = -167.1 kJ mol-1 ΔfH°[HCℓ(g)] = -127 kJ mol-1 | Bereken die entalpie-verandering vir die volgende reaksie met behulp van die toepaslike standaard vormingsentalpieë hieronder. ΔfH°[FeCℓ3(s)] = -412 kJ mol-1 ΔfH°[FeCℓ2(s)] = -360 kJ mol-1 ΔfH°[HCℓ(aq)] = -167.1 kJ mol-1 ΔfH°[HCℓ(g)] = -127 kJ mol-1 |
2 FeCℓ2(s) + 2 HCℓ(g) → 2 FeCℓ3(s) + H2(g)
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