Consider the claim that in a gender selection, the likelihood of having a baby girl is different from p = 0.6. and use the test statistic z = 3.44 (found from 18 girls in 21 births. Use
5% confidence of interval. First determine whether the given conditions result in a critical region in the right tail, left tail, or two tails, then use that theory to find the P-value. Interpret the P-value. Choose the best answer.

Question

Consider the claim that in a gender selection, the likelihood of having a baby girl is different from p = 0.6. and use the test statistic z = 3.44 (found from 18 girls in 21 births.  Use
5% confidence of interval. First determine whether the given conditions result in a critical region in the right tail, left tail, or two tails, then use that theory to find the P-value. Interpret the P-value.  Choose the best answer.

Answer

P-value = 2 x 0.0003 = 0.0006 since this
value
is inside 5% area then the likelihood of having a babby girl is different than
0.6

Answer

P-value = 2 x 0.03 = 0.06 since this
value
is inside 5% area then the likelihood of having a babby girl is different than
0.6

Answer

-0.0038    < 
(p2 - p1)   < -0.0016

The confidence interval limits do not
contain 0, implying that there is a significant difference between the two
proportions. The confidence interval suggests that the fatality rate is lower
for occupants in cars with used safety belt than for occupants in cars without
the use of it.

Answer

P-value = 2 x 0.003 = 0.006 since this
value
is inside 5% area then the likelihood of having a babby girl is different than
0.6

Answer

P-value = 2 x 0.007 = 0.014 since this
value
is inside 5% area then the likelihood of having a babby girl is different than
0.6

Answer

P-value = 2 x 0.03 = 0.06 since this
value
is ouside 5% area then the likelihood of having a babby girl is different than
0.6

Answer

P-value = 1.5579E+2 thus H(alternative) is accepted

Answer

P-value = 2 x 0.0003 = 0.0006 since this
value
is inside 2.5% area then the likelihood of having a babby girl is different than
0.6

Answer

P-value = 2 x 0.0007 = 0.0014 since this
value
is inside 5% area then the likelihood of having a babby girl is different than
0.6

Answer

P-value = 2 x 0.007 = 0.014 since this
value
is outside 5% area then the likelihood of having a babby girl is different than
0.6

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