The following program does not compile. Identify the reason(s) why. int main()
{ int know = 3;
switch (know)
{
case 3: printf("one
");
break;
case 1+1+1: printf("hi
");
break;
default: printf("bye
");
} return 0; }

Question

The following program does not compile. Identify the reason(s) why. int main() 
 {   int know = 3; 
 switch (know) 
 { 
   case 3:       printf("one
"); 
                 break; 
   case 1+1+1:   printf("hi
"); 
                 break; 
   default:      printf("bye
"); 
 }          return 0;            }

Accepted Answer

There is a duplicate case value '3'.

Answer

There is no break statement in the default branch.

Answer

One cannot have an expression as a case value.

Answer

Duplicate case values are possible, as long as the variable does not match the duplicated case.

Crowdly

The following program does not compile. Identify the reason(s) why. int main() ...

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