Giving the recurrence f( n )=2f(n-1)+3f(n-2) for n>=3. The roots are 3 and -1...
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Giving the recurrence f( n )=2f(n-1)+3f(n-2) for n>=3. The roots are 3 and -1. The constants c1=5/6 and c2=-1/2. The time complexity is:
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