✅ The verified answer to this question is available below. Our community-reviewed solutions help you understand the material better.
#include <stdio.h>
float MyFunction(int number) {
int result = 1;
for (int a = 0; a++ < number; a += 8) {
result = result * (a < 5 ? 3 : 2.5);
}
return result;
}
int main() {
int number=33;
float result = MyFunction(number);
printf("The result is: %.2f\n", result);
return 0;
}
Get Unlimited Answers To Exam Questions - Install Crowdly Extension Now!