What will be the output of the following code? #include #include int main() { int *arr = (int *)malloc(5 * sizeof(int)); for (int i = 0; i < 5; i++) { *(arr + i) = i * 2; } printf("%d\n", arr[3]); free(arr); return 0; }

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What will be the output of the following code?

#include <stdio.h>

#include <stdlib.h>

int main() {

int *arr = (int *)malloc(5 * sizeof(int));

for (int i = 0; i < 5; i++) {

*(arr + i) = i * 2;

}

printf("%d\n", arr[3]);

free(arr);

return 0;

}

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Undefined behavior

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