22. The equilibrium constant for the formation of calcium carbonate from the ion...
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22. The equilibrium constant for the formation of calcium carbonate from the ions in solution is 2.2 × 108 according to the reaction:
Ca2+(aq) + CO32–(aq) <=> CaCO3(s) K = 2.2 × 108.
What is the value of the equilibrium constant for the reverse of this reaction?
CaCO3(s) <=> Ca2+(aq) + CO3 2–(aq) K = ?????
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